Question Answers

Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 4 - Motion in 2 Dimension > The trajectory of a projectile in a vertical plane is y=ax −bx^2, where a, b are constants, and x and y are, respectively, the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______.

The trajectory of a projectile in a vertical plane is y=ax −bx^2, where a, b are constants, and x and y are, respectively, the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______.

and x and y are b are constants respectively the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______. The trajectory of a projectile in a vertical plane is y=ax −bx^2 Where a