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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The trajectory of a projectile in a vertical plane is y = ax – bx^2, where a and b are constants and x and y are, respectively, horizontal and vertical distances of the projectile from the point of projection.

The trajectory of a projectile in a vertical plane is y = ax – bx^2, where a and b are constants and x and y are, respectively, horizontal and vertical distances of the projectile from the point of projection.

horizontal and vertical distances of the projectile from the point of projection. respectively The trajectory of a projectile in a vertical plane is y = ax - bx^2 where a and b are constants and x and y are