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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > The trajectory of a projectile in a vertical plane is y=αx−βx^2 where α and β are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection theta and the maximum height attended H are respectively given by:

The trajectory of a projectile in a vertical plane is y=αx−βx^2 where α and β are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection theta and the maximum height attended H are respectively given by:

The logic circuit shown above is equivalent to :