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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 8 - Thermodynamics > The specific heat capacity of a metal at low temperature (T) is given as Cp (kJ K^-1kg-^1) = 32(T/400)^3. A 100 g vessel of this metal is to be cooled from 20 K to 4 K by a special refrigerator operating at room temperature (27°C). The amount of work required to cool the vessel is

The specific heat capacity of a metal at low temperature (T) is given as Cp (kJ K^-1kg-^1) = 32(T/400)^3. A 100 g vessel of this metal is to be cooled from 20 K to 4 K by a special refrigerator operating at room temperature (27°C). The amount of work required to cool the vessel is

n moles of an ideal gas undergoes a process A and B as shown in the figure. The maximum temperature of the gas during the process will be