Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0, then

The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0, then

The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0 then