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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The rectangular surface of area 8 cm × 4 cm of a black body at a temperature of 127 0 C emits energy at the rate of E per second. If the length and breadth of the surface are each reduced to half of the initial value and the temperature is raised 327 o C, the rate of emission of energy will become

The rectangular surface of area 8 cm × 4 cm of a black body at a temperature of 127 0 C emits energy at the rate of E per second. If the length and breadth of the surface are each reduced to half of the initial value and the temperature is raised 327 o C, the rate of emission of energy will become

A black body radiates energy at the rate of E W/ m^2 at a high temperature T K. When the temperture is reduced to T/2 K the radiant energy will be.........