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Sahay Sir > Question Answers > NCERT Exemplar Class 12 > Chemistry > The rate constant for the decomposition of hydrocarbons is 2.418×10^−5s^−1 at 546K. If the energy of activation is 179.9 kJ mol^−1, what will be the value of pre−exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418×10^−5s^−1 at 546K. If the energy of activation is 179.9 kJ mol^−1, what will be the value of pre−exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418×10^−5s^−1 at 546K. If the energy of activation is 179.9 kJ mol^−1 what will be the value of pre−exponential factor?