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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 6 - Work, Energy and Power > The potential energy of a particle oscillating on x-axis is given as U = 20 + (x – 2)2. Here, U is in joules and x in metres . Total mechanical energy of the particle is 36 J. Find the mean position kinetic energy of the particle respectively.

The potential energy of a particle oscillating on x-axis is given as U = 20 + (x – 2)2. Here, U is in joules and x in metres . Total mechanical energy of the particle is 36 J. Find the mean position kinetic energy of the particle respectively.

The potential energy of a particle oscillating on x-axis is given as U = 20 + (x - 2)2. Here U is in joules and x in metres . Total mechanical energy of the particle is 36 J. Find the mean position kinetic energy of the particle respectively.