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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The potential energy of a particle of mass m free to move along the x axis is given by U = (1/2) kx^2 for x 0 (x denotes the x coordinate of the particle and k is a positive constant).

The potential energy of a particle of mass m free to move along the x axis is given by U = (1/2) kx^2 for x 0 (x denotes the x coordinate of the particle and k is a positive constant).

The potential energy of a particle of mass m free to move along the x axis is given by U = (1/2) kx^2 for x 0 (x denotes the x coordinate of the particle and k is a positive constant).