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Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 7 - Work, Energy and Power > The potential energy of a particle in a force field is: U =A/r^2 ​− B/r​ where A and B are positive constants and r is the distance of particle from the centre of field. For stable equilibrium, the distance of the particle is :

The potential energy of a particle in a force field is: U =A/r^2 ​− B/r​ where A and B are positive constants and r is the distance of particle from the centre of field. For stable equilibrium, the distance of the particle is :

the distance of the particle is : The potential energy of a particle in a force field is: U =A/r^2 ​− B/r​ where A and B are positive constants and r is the distance of particle from the centre of field. For stable equilibrium