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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 6 - Work, Energy and Power > The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then , the maximum speed (in m/s) is

The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then , the maximum speed (in m/s) is

the maximum speed (in m/s) is The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then