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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The potential energy between two atoms in a diatomic molecule varies with x as U = a / x^12 – b/x^6, where a and b are positive constants. Find the equivalent spring constant

The potential energy between two atoms in a diatomic molecule varies with x as U = a / x^12 – b/x^6, where a and b are positive constants. Find the equivalent spring constant

The potential energy between two atoms in a diatomic molecule varies with x as U = a / x^12 - b/x^6 where a and b are positive constants. Find the equivalent spring constant