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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 2 - Kinematics > The position vector of a particle changes with time according to the relation r→(t)=15t^2iˆ+(4−20t^2)jˆ What is the magnitude of the acceleration (in ms^-2)?

The position vector of a particle changes with time according to the relation r→(t)=15t^2iˆ+(4−20t^2)jˆ What is the magnitude of the acceleration (in ms^-2)?

The position vector of a particle changes with time according to the relation r→(t)=15t^2iˆ+(4−20t^2)jˆ What is the magnitude of the acceleration (in ms^-2)?