The position vector of a particle changes with time according to the relation r→(t)=15 t^2 iˆ+(4−20 t^2)jˆ What is the magnitude of the acceleration at t = 1? The position vector of a particle changes with time according to the relation r→(t)=15 t^2 iˆ+(4−20 t^2)jˆ What is the magnitude of the acceleration at t = 1? February 13, 2021 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related