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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 2 - Kinematics > The position of a particle as a function of time t, is given by x(t) = at + bt^2 − ct^3 where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be

The position of a particle as a function of time t, is given by x(t) = at + bt^2 − ct^3 where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be

b and c are constants. When the particle attains zero acceleration is given by x(t) = at + bt^2 − ct^3 where a The position of a particle as a function of time t then its velocity will be