The phase difference between two waves represented by y1 = 10^−6sin [100t+50x+0.5]m y2 = 10^−6cos [100t+50x]m where x is expressed in metres and t is expressed in seconds is approximately The phase difference between two waves represented by y1 = 10^−6sin [100t+50x+0.5]m y2 = 10^−6cos [100t+50x]m where x is expressed in metres and t is expressed in seconds is approximately August 25, 2020 Category: Chapter 16 - Waves , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
