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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > The period of oscillation of a simple pendulum is T = 2π √ L/g . Measured value of ‘L’ is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of ‘g’ will be

The period of oscillation of a simple pendulum is T = 2π √ L/g . Measured value of ‘L’ is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of ‘g’ will be

the nature of graphical representation of velocity as a function of displacement is : When a particle executes SHM