THe number of atoms in 4.25 g of NH3 is approximately (a) 1 x 10^23 (b) 2 x 10^23 (c) 4 x 10^23 (d) 6 x 10^23 THe number of atoms in 4.25 g of NH3 is approximately (a) 1 x 10^23 (b) 2 x 10^23 (c) 4 x 10^23 (d) 6 x 10^23 November 18, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related