Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The maximum intensity in Young’s double slit experiment is I0. Distance between the slit is d = 5 lemda, where lemda is the wavelength of monochromatic light used in the experiment.

The maximum intensity in Young’s double slit experiment is I0. Distance between the slit is d = 5 lemda, where lemda is the wavelength of monochromatic light used in the experiment.

The maximum intensity in Young's double slit experiment is I0. Distance between the slit is d = 5 lemda where lemda is the wavelength of monochromatic light used in the experiment.