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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The length of a steel cylinder is kept constant by applying pressure at its two ends. When the temperature of rod is increased by 100 ∘ C from its initial temperature, the increase in pressure to be applied at its ends is (Y sted = 2 ×10^ 11 N/m ^ 2 , α steel 11 × 10 ^ −6 % C ,1 atm = 10 ^5 N/m ^2 )

The length of a steel cylinder is kept constant by applying pressure at its two ends. When the temperature of rod is increased by 100 ∘ C from its initial temperature, the increase in pressure to be applied at its ends is (Y sted = 2 ×10^ 11 N/m ^ 2 , α steel 11 × 10 ^ −6 % C ,1 atm = 10 ^5 N/m ^2 )

1 atm = 10 ^5 N/m ^2 ) the increase in pressure to be applied at its ends is (Y sted = 2 ×10^ 11 N/m ^ 2 The length of a steel cylinder is kept constant by applying pressure at its two ends. When the temperature of rod is increased by 100 ∘ C from its initial temperature α steel 11 × 10 ^ −6 % C