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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The ionization energy of hydrogen atom is -13.6 eV. The energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is (Avogadro’s constant = 6.022 x 10^23 )

The ionization energy of hydrogen atom is -13.6 eV. The energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is (Avogadro’s constant = 6.022 x 10^23 )

Assertion : Atomic orbital in an atom is designated by n L ml and ms. Reason : These are helpful in designating electron present in an orbital.