The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at : The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at : August 29, 2020 Category: Chapter 11 - Rotational Mechanics , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related