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Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 1 > Chapter 11 - Rotational Motion > The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t^3−6t^2. The torque on the wheel becomes zero at

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t^3−6t^2. The torque on the wheel becomes zero at

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t^3−6t^2. The torque on the wheel becomes zero at