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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 4 - Motion in Plane > The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y=(8t−5t^2)m and x=6t m, where t is in seconds. The velocity with which the projectile is projected is. (acceleration due to gravity = 9.8 m/s^2)

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y=(8t−5t^2)m and x=6t m, where t is in seconds. The velocity with which the projectile is projected is. (acceleration due to gravity = 9.8 m/s^2)

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y=(8t−5t^2)m and x=6t m where t is in seconds. The velocity with which the projectile is projected is. (acceleration due to gravity = 9.8 m/s^2)