The gravitational field due to a mass distribution is E = A/x2 If potential at infinity is zero and A be a constant. Then the potential at x is The gravitational field due to a mass distribution is E = A/x2 If potential at infinity is zero and A be a constant. Then the potential at x is September 20, 2020 Category: Chapter 10 - Gravitation , MTG NEET Physics , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
