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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 5 - Rotational Motion > The force of interaction between two atoms is given by F=αβ exp(− αkt x 2 ​ ); where x is the distance, k is the Boltzman constant and T is temperature and α and β are two constants. The dimension of β is

The force of interaction between two atoms is given by F=αβ exp(− αkt x 2 ​ ); where x is the distance, k is the Boltzman constant and T is temperature and α and β are two constants. The dimension of β is

k is the Boltzman constant and T is temperature and α and β are two constants. The dimension of β is The force of interaction between two atoms is given by F=αβ exp(− αkt x 2 ​ ); where x is the distance