Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The escape speed from earth’s surface is 11 km/s−1 . A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

The escape speed from earth’s surface is 11 km/s−1 . A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

calculate the escape speed on the surface of the planet of mass 7.5 x 10^25g and radius 1.6 x 10^6m. G =7.5 x 10^-8dyne cm^2 g-^2.