The equilibrium constant Kp for the following reaction at 191 degree C is 1.24 What is Kc ? B(s) + 2/3 F2(g) ⇌ BF3(g) The equilibrium constant Kp for the following reaction at 191 degree C is 1.24 What is Kc ? B(s) + 2/3 F2(g) ⇌ BF3(g) November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related