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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The equilibrium constant K, for the following reaction at 842°C is 7.90 x 10^-3. What is Kp, at same temperature?

The equilibrium constant K, for the following reaction at 842°C is 7.90 x 10^-3. What is Kp, at same temperature?

December 7, 2020
Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,

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