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Sahay Sir > Question Answers > N Awasthi Physical Chemistry > Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) > The equilibrium constant for the reaction in aqueous solution H3BO3 + glycerin ⇌ H3BO3 - glycerin is 0.90. How many moles of glycerin should be added per litre of 0.10 M H3 BO3 so that 80% of the H3 BO3 is converted to the boric-acid-glycerin complex?

The equilibrium constant for the reaction in aqueous solution H3BO3 + glycerin ⇌ H3BO3 - glycerin is 0.90. How many moles of glycerin should be added per litre of 0.10 M H3 BO3 so that 80% of the H3 BO3 is converted to the boric-acid-glycerin complex?

November 11, 2020
Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,

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The equilibrium constant for the reaction in aqueous solution H3BO3 ​+ glycerin ⇌ H3BO3 ​- glycerin is 0.90. How many moles of glycerin should be added per litre of 0.10 M H3 ​BO3 so that 80% of the H3 BO3 is converted to the boric-acid-glycerin complex?

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The equilibrium constant for the reaction in aqueous solution H3BO3 + glycerin ⇌ H3BO3 - glycerin is 0.90. How many moles of glycerin should be added per litre of 0.10 M H3 BO3 so that 80% of the H3 BO3 is converted to the boric-acid-glycerin complex?