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Sahay Sir > Question Answers > N Awasthi Physical Chemistry > Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) > The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a solution at equilibrium when pressure of RNH2(g) is 0.5 bar :

The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a solution at equilibrium when pressure of RNH2(g) is 0.5 bar :

The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a solution at equilibrium when pressure of RNH2(g) is 0.5 bar :