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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The equation of motion of a projectile is y = 12x – 3/4 x^2. The horizontal component of velocity is 3 m/s. What is the range of the projectile?

The equation of motion of a projectile is y = 12x – 3/4 x^2. The horizontal component of velocity is 3 m/s. What is the range of the projectile?

The equation of motion of a projectile is y = 12x - 3/4 x^2. The horizontal component of velocity is 3 m/s. What is the range of the projectile