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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The energy of an electron moving in nth Bohr’s orbit of an element is given by En=−13.6/n^2 Z^2 eV/ atom (Z=atomic number). The graph of E vs. Z^2 (keeping “n” constant) will be :

The energy of an electron moving in nth Bohr’s orbit of an element is given by En=−13.6/n^2 Z^2 eV/ atom (Z=atomic number). The graph of E vs. Z^2 (keeping “n” constant) will be :

The energy of an electron moving in nth Bohr's orbit of an element is given by En=−13.6/n^2 Z^2 eV/ atom (Z=atomic number). The graph of E vs. Z^2 (keeping "n" constant) will be :