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Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 2 > Chapter 1 - Electrostatics > The electric field strength due to a ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by E=1/4πε0 Qx/(R^2+x^2)3/2 At what distance from the centre will the electric field be maximum ?

The electric field strength due to a ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by E=1/4πε0 Qx/(R^2+x^2)3/2 At what distance from the centre will the electric field be maximum ?

The number of lines of forces coming out from +1 coulomb charge is