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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 17 - Dual Nature of Radiation > The electric field of light wave is given as E =10^−3cos(2πx/5×10^−7 −2π×6×10^14t)x^NC. This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given, E (in eV) = 12375/λ(inA)˙

The electric field of light wave is given as E =10^−3cos(2πx/5×10^−7 −2π×6×10^14t)x^NC. This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given, E (in eV) = 12375/λ(inA)˙

E (in eV) = 12375/λ(inA)˙ The electric field of light wave is given as E =10^−3cos(2πx/5×10^−7 −2π×6×10^14t)x^NC. This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given