The electric field in a region is given by → E = 2/5 E 0 ^ i + 3/5 E 0 ^ j with E0 = 4.0 × 10^3 N/C .The flux of this field through a rectangular surface area 0.4 m^2 parallel to the Y – Z plane is……….Nm^2C^–1 Red light differs from blue light as they have: September 28, 2021 Category: JEE Mains Physics 2002-2019 Solved Video Solutions , Practice Set 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related