The electric field associated with an electromagnetic wave in vacuum is given by E = i (cap) 40 cos (kz − 6 × 10^8t), where E, z and t are in volt per meter, meter and second respectively. The value of wave vector k is meter and second respectively. The value of wave vector k is The electric field associated with an electromagnetic wave in vacuum is given by E = i (cap) 40 cos(kz − 6×10^8t) where E z and t are in volt per meter August 20, 2020 Category: Chapter 28 - Electromagnetic Waves , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related The electric field of a plane electromagnetic wave is given by E =E0i^cos(kz)cos(ωt) The corresponding magnetic field B is then given by :A plane electromagnetic wave in the visible region is moving along the Z-direction. The frequency of the wave is 0.5×10^(15) Hz and the electric field at any point is varying sinusoidally with time with an amplitude of 1V/m. The average value of energy densities of the electric and magnetic fields respectively areA plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by vector B = 5 x 10^-8 j T. The corresponding electric field vector E is (speed of light c = 3 × 10^8 ms–1)
