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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The edge of unit cell of FCC Xe crystal is 620 pm . The radius of Xe atom is (a) 219.25 pm (b) 235.16 pm (c) 189.37 pm (d) 209.87 pm

The edge of unit cell of FCC Xe crystal is 620 pm . The radius of Xe atom is (a) 219.25 pm (b) 235.16 pm (c) 189.37 pm (d) 209.87 pm

The edge of unit cell of FCC Xe crystal is 620 pm . The radius of Xe atom is (a) 219.25 pm (b) 235.16 pm (c) 189.37 pm (d) 209.87 pm