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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 5 - Rotational Motion > The dimensions of 1/2Enote E^2 (Enote : permitivity of free space ;E : electric field) is (a) [MLT^-1] (b) [ML^2T^-2] (c) [MLT^-2] (d) [ML^2 T^-1]

The dimensions of 1/2Enote E^2 (Enote : permitivity of free space ;E : electric field) is (a) [MLT^-1] (b) [ML^2T^-2] (c) [MLT^-2] (d) [ML^2 T^-1]

The dimensions of 1/2Enote E^2 (Enote : permitivity of free space ;E : electric field) is (a) [MLT^-1] (b) [ML^2T^-2] (c) [MLT^-2] (d) [ML^2 T^-1]