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Sahay Sir > Question Answers > MTG NEET Physics > Part 2 > Chapter 11 - Dual Nature of Radiation and Matter > The de Broglie wavelength of an electron with kinetic energy 120 eV is (Given h=6.63×10^−34 Js, me = 9×11^−31 kg,1e=1.6×10^−19 C):

The de Broglie wavelength of an electron with kinetic energy 120 eV is (Given h=6.63×10^−34 Js, me = 9×11^−31 kg,1e=1.6×10^−19 C):

1e=1.6×10^−19 C): me = 9×11^−31 kg The de Broglie wavelength of an electron with kinetic energy 120 eV is (Given h=6.63×10^−34 Js