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Sahay Sir > Question Answers > NCERT Class 10 > Maths > Chapter 13 - Surface Areas and Volumes > The curved surface area of frustum of a cone is π/(r1+r2), where l = h^2 + (r1+r2)^2−−√,r1 and r2 are the radii of two ends of the frustum and h s the vertical height.

The curved surface area of frustum of a cone is π/(r1+r2), where l = h^2 + (r1+r2)^2−−√,r1 and r2 are the radii of two ends of the frustum and h s the vertical height.

r1 and r2 are the radii of two ends of the frustum and h s the vertical height. The curved surface area of frustum of a cone is π/(r1+r2) where l = h^2 + (r1+r2)^2−−√