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Sahay Sir > Question Answers > JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 > Chemistry > Chapter 7 - Equilibrium > The concentration of hydrogen ions in a 0.2 M solution of formic acid is 6.4×10^−3 mol L^−1. To this solution, sodium formate is added so as to adjust the concentration of sodium formate to 1 mol L^−1. What will be the pH of this solution? The dissociation constant of formic acid is 2.4×10^−4 and the degree of dissociation of sodium formate is 0.75.

The concentration of hydrogen ions in a 0.2 M solution of formic acid is 6.4×10^−3 mol L^−1. To this solution, sodium formate is added so as to adjust the concentration of sodium formate to 1 mol L^−1. What will be the pH of this solution? The dissociation constant of formic acid is 2.4×10^−4 and the degree of dissociation of sodium formate is 0.75.

The concentration of hydrogen ions in a 0.2 M solution of formic acid is 6.4×10^−3 mol L^−1. To this solution What is the pH of a 0.50 M aqueous NaCN solution? pKb​ of CN− is 4.70.