The compound on reaction with NaIO4 in the presence of KMnO4 gives (a) CH3CHO + CO2 (b) CH3COCH3 (c0 CH3COCH3 + CH3COOH The compound on reaction with NaIO4 in the presence of KMnO4 gives (a) CH3CHO + CO2 (b) CH3COCH3 (c0 CH3COCH3 + CH3COOH December 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
