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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The cell in the circuit shows in Fig is ideal. The coil has an inductance of 4 mH and a resistance of 2mΩ. The switch is closed at t=0. The amount of energy stored in the inductor at t = 2 s is (take e = 3)

The cell in the circuit shows in Fig is ideal. The coil has an inductance of 4 mH and a resistance of 2mΩ. The switch is closed at t=0. The amount of energy stored in the inductor at t = 2 s is (take e = 3)

C = 2μF E 1 = 3 V and E 2 = 7 V In Fig. key K is closed at t=0. After a long time L = 4 mH respectively the potential difference between A and B is zero the value of R will be [ r 1 = r 2 = 1 Ω where r1 and r2 are the internal resistances of cells E1 and E2