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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The capacitors shown in the circuit have capacitance C1 = C and C2 = 3C and they have been charged to potenitals V1=2V0 and V2=3V0 respectively. Switch S is closed to connect them to the inductor L. (a) Find the maximum current through the inductor (b) Find potential difference across C1 and C2 when the current in the inductor is maximum.

The capacitors shown in the circuit have capacitance C1 = C and C2 = 3C and they have been charged to potenitals V1=2V0 and V2=3V0 respectively. Switch S is closed to connect them to the inductor L. (a) Find the maximum current through the inductor (b) Find potential difference across C1 and C2 when the current in the inductor is maximum.

a or b c or d E = 120 V In the circuit shown in fig In the circuit shown in Figure Initially the 900μF capacitor is charged to 100 V and the 100μF capacitor is uncharged in Fig. Then switch S2 is closed for time t1 is at higher potential? (c) What is the potential difference Vcd across the inductor L? (d) Which point is at steady state. if R1 = R2= R3 =R and the current through each resistor is i. Find the currents through the resistors immediately after the switch S is opened. R1 = 30.0 Ω R2 =50.0Ω and L = 0.200 H. Switch S is closed at t=0. Just after the switch is closed.(a) What is the potential difference Vab across the inductor R1? (b) Which point