Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 31 - Nuclei > The binding energy per nucleon of 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction 3Li7 and 2He4 is

The binding energy per nucleon of 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction 3Li7 and 2He4 is

The binding energy per nucleon of 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 MeV then the energy of proton in the reaction 3Li7 and 2He4 is