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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The amplitude of a wave disturbance propagating along positive X-axis is given by y = 1 / (1 + x^2) at t = 0 and y = 1 / (1 + (x – 2)^2) at t = 4 s where x and y are in metre. The

The amplitude of a wave disturbance propagating along positive X-axis is given by y = 1 / (1 + x^2) at t = 0 and y = 1 / (1 + (x – 2)^2) at t = 4 s where x and y are in metre. The

The amplitude of a wave disturbance propagating along positive X-axis is given by y = 1 / (1 + x^2) at t = 0 and y = 1 / (1 + (x - 2)^2) at t = 4 s where x and y are in metre. The