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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The acceleration a in ms^-2 of a particle is given by a = 3t^2 + 2t +2, where t is the time. If the particle starts out with a velocity v =v2 m/s at t = 0, then find the velocity at the end of 2 s.

The acceleration a in ms^-2 of a particle is given by a = 3t^2 + 2t +2, where t is the time. If the particle starts out with a velocity v =v2 m/s at t = 0, then find the velocity at the end of 2 s.

The acceleration a in ms^-2 of a particle is given by a = 3t^2 + 2t + 2 then find the velocity at the end of 2 s. where t is the time. If the particle starts out with a velocity v =v2 m/s at t = 0