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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > The 226Ra88 nucleus undergoes alpha decay to 226Rn88. Calculate the amount of energy liberated in this decay. Take the mass of 226Ra88 to be 226.025 402 u, that of 226Rn88 to be 222.017571 u,

The 226Ra88 nucleus undergoes alpha decay to 226Rn88. Calculate the amount of energy liberated in this decay. Take the mass of 226Ra88 to be 226.025 402 u, that of 226Rn88 to be 222.017571 u,

that of 226Rn88 to be 222.017571 u The 226Ra88 nucleus undergoes alpha decay to 226Rn88. Calculate the amount of energy liberated in this decay. Take the mass of 226Ra88 to be 226.025 402 u