Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be : Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be : November 28, 2020 Category: Chapter 18 - Atoms and Nuclei , JEE Mains Physics 2002-2019 Solved Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related